+1245 Circle A is in the interior of circle B. The diameter of circle B is 16 cm. What is the diameter of circle A for which the ratio of the shaded area to the area of circle A is 3:1?
+4625 We know that the area of the shaded region plus the area of circle A equals the Area of Circle B. Since the shaded area: area of the circle, 3:1, we have 3x+x=64π4x=64π,x=16π . Directly, we get π∗r2=16π, so r2=16,r=4. Remember that length can't be negative! Thus, the diameter of circle A is 4∗2=8 cm.
+4625 We know that the area of the shaded region plus the area of circle A equals the Area of Circle B. Since the shaded area: area of the circle, 3:1, we have 3x+x=64π4x=64π,x=16π . Directly, we get π∗r2=16π, so r2=16,r=4. Remember that length can't be negative! Thus, the diameter of circle A is 4∗2=8 cm.
