Find the solutions $x$ of the equation $$2ix^2+x+3i=0.$$
The polynomial can be factored:
(2x - 3i)(ix - 1) = 0
Setting each factor to zero and solving yields the two roots:
2x - 3i = 0
2x = 3i
x = 3i/2
ix - 1 = 0
ix = 1
x = -i (where we use the fact that 1/i = -i)
Thank you!
