+0  
 
0
62
1
avatar+180 

The number of peanuts in bags is normally distributed with a mean of 193.8 peanuts and a standard deviation of 4.1 peanuts.

What is the z-score of a bag containing 185 peanuts?

−2.47

−2.15

−1.90

−1.22

 Feb 17, 2020
 #1
avatar+109740 
+1

The  "formula"  for a z score  is

 

[  given score  - mean score ]  / standard deviation  =  z  score

 

So....

 

 

[ 185 - 193.8 ] / 4.1 ≈  -2.15

 

 

cool cool cool

 Feb 17, 2020

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