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The perimeter of a triangle is 71 cm. The first side is 3 cm shorter than the second side, and the third side is twice as long as the first side. Find the length of the longest side.

 Feb 5, 2020

Best Answer 

 #1
avatar+266 
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Let us make some equations: where the first side=\(x-3\), the second side=\(x\), and third side=\(2(x-3)\).

\(x-3+x+2(x-3)=71\)

\(x+x+2x-6-3=71\)

\(4x-9=71\)

\(4x=80\)

\(x=20\)

We need to find the longest side, which is the third side, or\(2(x-3)\).

\(2((20)-3)\)

\(\rightarrow34\leftarrow\)

.
 Feb 5, 2020
 #1
avatar+266 
+2
Best Answer

Let us make some equations: where the first side=\(x-3\), the second side=\(x\), and third side=\(2(x-3)\).

\(x-3+x+2(x-3)=71\)

\(x+x+2x-6-3=71\)

\(4x-9=71\)

\(4x=80\)

\(x=20\)

We need to find the longest side, which is the third side, or\(2(x-3)\).

\(2((20)-3)\)

\(\rightarrow34\leftarrow\)

tomsun Feb 5, 2020

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