The perimeter of a triangle is 71 cm. The first side is 3 cm shorter than the second side, and the third side is twice as long as the first side. Find the length of the longest side.
+299 Let us make some equations: where the first side=\(x-3\), the second side=\(x\), and third side=\(2(x-3)\).
\(x-3+x+2(x-3)=71\)
\(x+x+2x-6-3=71\)
\(4x-9=71\)
\(4x=80\)
\(x=20\)
We need to find the longest side, which is the third side, or\(2(x-3)\).
\(2((20)-3)\)
\(\rightarrow34\leftarrow\)
+299 Let us make some equations: where the first side=\(x-3\), the second side=\(x\), and third side=\(2(x-3)\).
\(x-3+x+2(x-3)=71\)
\(x+x+2x-6-3=71\)
\(4x-9=71\)
\(4x=80\)
\(x=20\)
We need to find the longest side, which is the third side, or\(2(x-3)\).
\(2((20)-3)\)
\(\rightarrow34\leftarrow\)
