The perimeter of a triangle is 71 cm. The first side is 3 cm shorter than the second side, and the third side is twice as long as the first side. Find the length of the longest side.
Let us make some equations: where the first side=x−3, the second side=x, and third side=2(x−3).
x−3+x+2(x−3)=71
x+x+2x−6−3=71
4x−9=71
4x=80
x=20
We need to find the longest side, which is the third side, or2(x−3).
2((20)−3)
→34←
