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# help

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The perimeter of a triangle is 71 cm. The first side is 3 cm shorter than the second side, and the third side is twice as long as the first side. Find the length of the longest side.

Feb 5, 2020

#1
+272
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Let us make some equations: where the first side=$$x-3$$, the second side=$$x$$, and third side=$$2(x-3)$$.

$$x-3+x+2(x-3)=71$$

$$x+x+2x-6-3=71$$

$$4x-9=71$$

$$4x=80$$

$$x=20$$

We need to find the longest side, which is the third side, or$$2(x-3)$$.

$$2((20)-3)$$

$$\rightarrow34\leftarrow$$

.
Feb 5, 2020

#1
+272
+2

Let us make some equations: where the first side=$$x-3$$, the second side=$$x$$, and third side=$$2(x-3)$$.

$$x-3+x+2(x-3)=71$$

$$x+x+2x-6-3=71$$

$$4x-9=71$$

$$4x=80$$

$$x=20$$

We need to find the longest side, which is the third side, or$$2(x-3)$$.

$$2((20)-3)$$

$$\rightarrow34\leftarrow$$

tomsun Feb 5, 2020