A spherical orange is cut about the vertical axis into 8 equal slices. What is the ratio of the total surface area of the 8 slices to that of the original orange?

Guest May 24, 2020

#1**+1 **

\(SA= 4 \pi r^2\)

Cros section through middle \(A = \pi r^2\)

SA of a slice is A + SA/8

SA of all 8 pieces = 8A+ SA

\(\text{Surface are of slices : surface are of whole orange}\\~\\ 8A+SA:SA\\~ 8\pi r^2+4\pi r^2:4\pi r^2\\ 12\pi r^2:4\pi r^2\\\)

And you can finish it.

Melody May 24, 2020

#2**+1 **

A spherical orange is cut about the vertical axis into 8 equal slices. What is the ratio of the total surface area of the 8 slices to that of the original orange?

**Hello Guest!**

\(A_{orange}=4\pi r^2\\ A_{slices}=4\pi r^2+8\pi r^2=12\pi r^2\)

\(\dfrac{A_{orange}}{A_{slices}}=\dfrac{1}{3}\)

!

asinus May 24, 2020