A spherical orange is cut about the vertical axis into 8 equal slices. What is the ratio of the total surface area of the 8 slices to that of the original orange?
+118608 \(SA= 4 \pi r^2\)
Cros section through middle \(A = \pi r^2\)
SA of a slice is A + SA/8
SA of all 8 pieces = 8A+ SA
\(\text{Surface are of slices : surface are of whole orange}\\~\\ 8A+SA:SA\\~ 8\pi r^2+4\pi r^2:4\pi r^2\\ 12\pi r^2:4\pi r^2\\\)
And you can finish it. 
+14903 A spherical orange is cut about the vertical axis into 8 equal slices. What is the ratio of the total surface area of the 8 slices to that of the original orange?
Hello Guest!
\(A_{orange}=4\pi r^2\\ A_{slices}=4\pi r^2+8\pi r^2=12\pi r^2\)
\(\dfrac{A_{orange}}{A_{slices}}=\dfrac{1}{3}\)
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