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# help

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A spherical orange is cut about the vertical axis into 8 equal slices.  What is the ratio of the total surface area of the 8 slices to that of the original orange?

May 24, 2020

#1
+112011
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$$SA= 4 \pi r^2$$

Cros section through middle    $$A = \pi r^2$$

SA of a slice is  A + SA/8

SA of all 8 pieces = 8A+ SA

$$\text{Surface are of slices : surface are of whole orange}\\~\\ 8A+SA:SA\\~ 8\pi r^2+4\pi r^2:4\pi r^2\\ 12\pi r^2:4\pi r^2\\$$

And you can finish it.

May 24, 2020
#2
+10807
+1

A spherical orange is cut about the vertical axis into 8 equal slices.  What is the ratio of the total surface area of the 8 slices to that of the original orange?

Hello Guest!

$$A_{orange}=4\pi r^2\\ A_{slices}=4\pi r^2+8\pi r^2=12\pi r^2$$

$$\dfrac{A_{orange}}{A_{slices}}=\dfrac{1}{3}$$

!

May 24, 2020