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A spherical orange is cut about the vertical axis into 8 equal slices.  What is the ratio of the total surface area of the 8 slices to that of the original orange?

 

 May 24, 2020
 #1
avatar+110074 
+1

\(SA= 4 \pi r^2\)

 

Cros section through middle    \(A = \pi r^2\)

 

SA of a slice is  A + SA/8

SA of all 8 pieces = 8A+ SA

 

\(\text{Surface are of slices : surface are of whole orange}\\~\\ 8A+SA:SA\\~ 8\pi r^2+4\pi r^2:4\pi r^2\\ 12\pi r^2:4\pi r^2\\\)

 

 

And you can finish it.     laugh

 May 24, 2020
 #2
avatar+9766 
+1

A spherical orange is cut about the vertical axis into 8 equal slices.  What is the ratio of the total surface area of the 8 slices to that of the original orange?

 

Hello Guest!

 

\(A_{orange}=4\pi r^2\\ A_{slices}=4\pi r^2+8\pi r^2=12\pi r^2\)

 

\(\dfrac{A_{orange}}{A_{slices}}=\dfrac{1}{3}\)

laugh  !

 May 24, 2020

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