Define \(f(x)=\frac{1+x}{1-x}\) and \(g(x)=\frac{-2}{x+1}\). Find the value of \(g(f(g(f(\dotsb g(f(12)) \dotsb ))))\) where the function f is applied 8 times, and the function g is applied 8 times, alternating between the two.
f(12) = -13/11
g(-13/11) = 22
f(22) = -23/21
g(23/21) = 21.
So it looks like each round it subtracts 1. 23 - 8 = 15
=^._.^=
+273 
