What is the smallest multiple of 72, where every digit is 0 or 1?
\(2^x=72y\) where x and y are integers.
I don't think there is one....
\(72=9*8=2^3+3^2 \)
\(2^x=72y \)
the prime factors on the left side is just 2 and on the right side it is 2 and 3
I do not think any integer answers are possible.....
