+0  
 
+1
227
1
avatar+545 

If a is congruent to 62 (mod 99) and b is congruent to 75 (mod 99), then for what integer n in the set {1000, 1001, 1002, 1003...  1098} is it true that a-b is congruent to n (mod 99)?

 Jul 12, 2019
 #1
avatar+7763 
0

\(a - b \equiv n \pmod{99}\\ 62 - 75 \equiv n \pmod{99}\\ n\equiv -13 \pmod{99}\\ n \equiv 86 \pmod{99}\\ n \equiv 990 + 86 \pmod{99}\\ n \equiv 1076\pmod{99}\)

So n is 1076

 Jul 13, 2019

31 Online Users

avatar
avatar
avatar