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In triangle $ABC$, $\angle A = 30^\circ$ and $\angle B = 60^\circ$. Point $X$ is on side $\overline{AC}$ such that line segment $\overline{BX}$ bisects $\angle ABC$. If $AB = 12$, then find the area of triangle $BXA$.

 Apr 25, 2020
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By the angle bisector theorem, the area of triangle BXA is 15*sqrt(2).

 Apr 25, 2020

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