Ok , so for this it's best to treat the > as if it was an = '
so it will be -35+3x = 5(x-5)
So first you will need to isolate the variable "X"
-35+3x=5x-25
add the 25 to both sides
so , -10+3x=5x
subtract the 3x
-10=2 x , then divide the 2x
x=-5
now since its negative the >switches to <
x<-5
