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A box contains 5 yellow balls, 3 blue, and 1 red ball. Two balls are drawn at random. Find the probability that the two balls have the same color.

 Jul 17, 2019
 #1
avatar+106535 
+2

Assuming that the balls are drawn sequentially........we can either draw two yelow balls or two blue balls

 

P( two yellow balls )  =  5/9 * 4/8  =  20/72  = 5/18

P(two blue balls) = 3/9 * 2/8  = 6/72  =  1/12

 

So.....the total probability is  5/18 + 1/12  =   [10 + 3 ] / 36  =  13 / 36

 

 

cool cool cool

 Jul 17, 2019
edited by CPhill  Jul 18, 2019
 #2
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+1

Edited Chris' answer:

Assuming that the balls are drawn sequentially........we can either draw two BLUE balls or two yellow balls

 

P( two YELLOW balls )  =  5/9 * 4/8  =  20/72  = 5/18

P(two blue balls) = 3/9 * 2/8  = 6/72  =  1/12

 

So.....the total probability is  5/18 + 1/12  =   [10 + 3 ] / 36  =  13 / 36

 Jul 18, 2019
 #3
avatar+106535 
+1

OOPS!!!....thx, guest!!!....correction made

 

 

cool cool cool

CPhill  Jul 18, 2019

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