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A family has 8 girls and four boys. A total of 2 children must be chosen to speak on the behalf of a family at a local benefit. What is the probability that 2 girls and no boys are chosen

Guest Jun 15, 2017
 #1
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Prob first child is a girl = 8/12

Prob second child is a girl = 7/11

 

So prob of two girls = (8/12)*(7/11) → 14/33 or 0.424242...

Alan  Jun 15, 2017

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