A family has 8 girls and four boys. A total of 2 children must be chosen to speak on the behalf of a family at a local benefit. What is the probability that 2 girls and no boys are chosen
Prob first child is a girl = 8/12
Prob second child is a girl = 7/11
So prob of two girls = (8/12)*(7/11) → 14/33 or 0.424242...