+0  
 
+1
280
4
avatar+205 

198/27+6(2+8(1-2)+(11-3)+5)/2=28

How and why?

 Sep 23, 2020
 #1
avatar+30 
+1

This is false

 

\(\frac{198}{27}+\frac{6(2+8(1-2)+(11-3)+5)}{2}\)

\(\)\(=\frac{198}{27}+\frac{6\cdot(2+8\cdot-1+8+5)}{2}\)

\(=\frac{198}{27}+\frac{6\cdot7}{2}\)

\(=\frac{22}{3}+\frac{6\cdot7}{2}\)

\(=\frac{22}{3}+\frac{42}{2}\)

\(=\frac{85}{3}\)

\(=28 \frac{1}{3}\)

 

Hope this helped! smiley

 Sep 23, 2020
edited by VioIynx  Sep 23, 2020
 #2
avatar+205 
0

According so my scientific calculator it's 28, no fractions, same thing on answer section thing

 Sep 23, 2020
 #3
avatar+30 
0

Hmm.. Maybe they just rounded it? Or you typed in the question wrong?

 

According to Wolframalpha, it's 28 1/3, and when I solved it I got the same thing.

 Sep 23, 2020
 #4
avatar+1001 
+2

Hi tacobell, I think that Violynx is correct.

 Sep 23, 2020

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