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This is false. 

\(\frac{198}{27}+\frac{6(2+8(1-2)+(11-3)+5)}{2}\)

\(\)\(=\frac{198}{27}+\frac{6\cdot(2+8\cdot-1+8+5)}{2}\)

\(=\frac{198}{27}+\frac{6\cdot7}{2}\)

\(=\frac{22}{3}+\frac{6\cdot7}{2}\)

\(=\frac{22}{3}+\frac{42}{2}\)

\(=\frac{85}{3}\)

\(=28 \frac{1}{3}\)

Hope this helped! 

According so my scientific calculator it's 28, no fractions, same thing on answer section thing

Hmm.. Maybe they just rounded it? Or you typed in the question wrong?

According to Wolframalpha, it's 28 1/3, and when I solved it I got the same thing.

Hi tacobell, I think that Violynx is correct.