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In the trapezium ABCD where AB is parallel to CD, AB is 3 units longer than CD, BC = 5, and AD is perpendicular to AB.  Given that the area of the trapezium is 34, find the perimeter of the trapezium.

 

 Dec 26, 2019
 #1
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The perimeter of the trapezium is  26 units.  indecision  

 Dec 26, 2019
 #2
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Since AB  is 3 units longer than CD.....then the height of the trapezium  = 4  =AD

 

We have that

 

34  = (1/2)(4)  ( CD  + 3  + CD)

 

17  =  3 + 2CD

 

14  =  2CD

 

7  = CD 

 

10 = AB

 

4 = AD

 

5  = BC

 

So.....the perimeter  =   CD + AB  +  AD  +  BC   =  7  + 10   +  4   +  5    =  26

 

 

 

cool cool cool

 Dec 26, 2019

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