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For what values of x is \(2x^2+8x\le-6\)? Express your answer in interval notation.

 Jul 25, 2019
 #1
avatar+24418 
0

2x^2+8x+6 <= 0

x^2 + 4x+3<=0

(x+1)(x+3)<=0

 

x = -1 and -3 for the equation to EQUAL zero 

 

Now from - infinity to -3 it is greater than 0   and from -1 to + infinity it is greater than zero

so the only interval   is from  -3 to -1 that satisfies the equation

[-3,-1]

 Jul 25, 2019
 #2
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0

-3=x<=-1

 Jul 25, 2019
 #3
avatar+24418 
0

Deleted ....never mind

ElectricPavlov  Jul 26, 2019
edited by ElectricPavlov  Jul 26, 2019
 #4
avatar+1710 
-1

Why do you keep deleting?

tommarvoloriddle  Jul 26, 2019

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