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How many 5-digit numbers without repetition of digits can be formed using the digits 0, 2, 4, 6, 8?

 Dec 2, 2019
 #1
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+1

Assuming that starting with "0" is not valid, then we have:

 

5! - 4! =96 - 5-digit numbers are possible. 

 Dec 2, 2019
 #2
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+1

There are 4 options for digit 1 (ignoring 0)

4 for digit 2

3 for 3

2 for 4 and 1 for 5

so 4*4*3*2*1=96

96 5 digit numbers

 Dec 2, 2019

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