How many 5-digit numbers without repetition of digits can be formed using the digits 0, 2, 4, 6, 8?
Assuming that starting with "0" is not valid, then we have:
5! - 4! =96 - 5-digit numbers are possible.
There are 4 options for digit 1 (ignoring 0)
4 for digit 2
3 for 3
2 for 4 and 1 for 5
so 4*4*3*2*1=96
96 5 digit numbers
