If \[f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases} \]then for how many values of $x$ is $f(f(x)) = 5$?
Start with a sketch of the function.
Then find x if f(x)=5
Get back to me with your answer.
