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If \[f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases} \]then for how many values of $x$ is $f(f(x)) = 5$?

 Dec 22, 2020
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Start with a sketch of the function.

 

Then find x   if   f(x)=5

 

Get back to me with your answer.

 Dec 22, 2020

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