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A certain circle can be represented by the following equation: x^2 + y^2 - 6x - 6y + 2 = 0

 

 Apr 22, 2020
 #1
avatar+928 
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Rearrange the terms to make the equation

 

\({x}^{2}-6x+{y}^{2}-6y=-2\)

 

Complete the square for x and y to get

 

\({x}^{2}-6x+9+{y}^{2}-6y+9=16\)

 

Factor

 

\((x-3)^2+(y-3)^2=4^2\)

 

From this form of the equation, we know that the center of the circle is (3, 3) and the radius is 4.

 

If you don't understand how to get the center and radius from that equation...

 

Make the equation of the circle in the form

 

\((x-h)^2+(y-k)^2=r^2\)

 

Where \((h, k)\) is the center of the circle and \(r\) is the radius.

 

Apply this to the equation above and you will get your solution.

 Apr 22, 2020
 #2
avatar+928 
+1

Btw, since this is from Khan Academy, there should be multiple videos and resources explaing how to do these types of problems.

HELPMEEEEEEEEEEEEE  Apr 22, 2020

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