A certain circle can be represented by the following equation: x^2 + y^2 - 6x - 6y + 2 = 0

Guest Apr 22, 2020

#1**+1 **

Rearrange the terms to make the equation

\({x}^{2}-6x+{y}^{2}-6y=-2\)

Complete the square for x and y to get

\({x}^{2}-6x+9+{y}^{2}-6y+9=16\)

Factor

\((x-3)^2+(y-3)^2=4^2\)

From this form of the equation, we know that the **center of the circle is (3, 3) and the radius is 4**.

If you don't understand how to get the center and radius from that equation...

Make the equation of the circle in the form

\((x-h)^2+(y-k)^2=r^2\)

Where \((h, k)\) is the center of the circle and \(r\) is the radius.

Apply this to the equation above and you will get your solution.

HELPMEEEEEEEEEEEEE Apr 22, 2020

#2**+1 **

Btw, since this is from Khan Academy, there should be multiple videos and resources explaing how to do these types of problems.

HELPMEEEEEEEEEEEEE
Apr 22, 2020