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How many 5-digit numbers without repetition of digits can be formed using the digits 0, 2, 4, 6, 8?

 Jun 22, 2020
 #1
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There are 4 choices for the first digit: cant be 0.

 

There are also 4 for the second, 3 for the third, 2 for the fourth, 1 for the fifth.

 

Thus, 4*4*3*2 = 96 ways.

 Jun 22, 2020
 #2
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Another way:

 

5!  -  4!  = 96 arrangements.

 Jun 22, 2020
 #3
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Yes, thank you.

 

Didn't think of that.

hugomimihu  Jun 22, 2020

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