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How many integers satisfy the inequality $(x+3)^{2}\leq1$?

Guest Mar 2, 2018

Best Answer 

 #1
avatar+12266 
+2

(x+3)^2 <= 1

x^2 +6x +9 -1 <=0

x^2 +6x +8 <=0

(x+4)(x+2) <=0

From -2 to minus 4 solves this      -4  -3   -2   Three integers  

ElectricPavlov  Mar 2, 2018
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1+0 Answers

 #1
avatar+12266 
+2
Best Answer

(x+3)^2 <= 1

x^2 +6x +9 -1 <=0

x^2 +6x +8 <=0

(x+4)(x+2) <=0

From -2 to minus 4 solves this      -4  -3   -2   Three integers  

ElectricPavlov  Mar 2, 2018

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