How many integers satisfy the inequality $(x+3)^{2}\leq1$?
(x+3)^2 <= 1
x^2 +6x +9 -1 <=0
x^2 +6x +8 <=0
(x+4)(x+2) <=0
From -2 to minus 4 solves this -4 -3 -2 Three integers
+36916 +36916 
