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Four positive integers A, B, C and D have a sum of 36. If A + 2 = B – 2 = C × 2 = D ÷ 2, what is the value of the product A × B × C × D?

 May 22, 2020

Best Answer 

 #1
avatar+732 
+2

hi guest!

 

so first we can express everything in terms of A.

 

A=A

 

A+2=B-2, B=A+4

 

A+2=2C, C=A/2+1

 

A+2=D/2, D=2A+4

 

So, we can now add this all up. 

 

A+A+4+A/2+1+2A+4=36

4.5A+9=36

4.5A=27

A=6

 

Now, we can find the values of B, C, and D.

A=6

B=10

C=4

D=16

 

\(6 \cdot 10 \cdot 4 \cdot 16= \boxed{3840}\)

 

I hope this helped you!

:)

 May 22, 2020
 #1
avatar+732 
+2
Best Answer

hi guest!

 

so first we can express everything in terms of A.

 

A=A

 

A+2=B-2, B=A+4

 

A+2=2C, C=A/2+1

 

A+2=D/2, D=2A+4

 

So, we can now add this all up. 

 

A+A+4+A/2+1+2A+4=36

4.5A+9=36

4.5A=27

A=6

 

Now, we can find the values of B, C, and D.

A=6

B=10

C=4

D=16

 

\(6 \cdot 10 \cdot 4 \cdot 16= \boxed{3840}\)

 

I hope this helped you!

:)

lokiisnotdead May 22, 2020

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