Four positive integers A, B, C and D have a sum of 36. If A + 2 = B – 2 = C × 2 = D ÷ 2, what is the value of the product A × B × C × D?
+738 hi guest!
so first we can express everything in terms of A.
A=A
A+2=B-2, B=A+4
A+2=2C, C=A/2+1
A+2=D/2, D=2A+4
So, we can now add this all up.
A+A+4+A/2+1+2A+4=36
4.5A+9=36
4.5A=27
A=6
Now, we can find the values of B, C, and D.
A=6
B=10
C=4
D=16
\(6 \cdot 10 \cdot 4 \cdot 16= \boxed{3840}\)
I hope this helped you!
:)
+738 hi guest!
so first we can express everything in terms of A.
A=A
A+2=B-2, B=A+4
A+2=2C, C=A/2+1
A+2=D/2, D=2A+4
So, we can now add this all up.
A+A+4+A/2+1+2A+4=36
4.5A+9=36
4.5A=27
A=6
Now, we can find the values of B, C, and D.
A=6
B=10
C=4
D=16
\(6 \cdot 10 \cdot 4 \cdot 16= \boxed{3840}\)
I hope this helped you!
:)
