#3**+2 **

Sure, I can try! First, we can call the side length of the square "x". The area of this orginal square would be x^2. Next, if the length of the side of the square was doubled, then one side would have a length of 2*x = 2x. The area of this new sqaure would be (2x)^2 = 4x^2. Therefore, the ratio of the areas of the original sqaure and the area of the new sqaure is x^2 / 4x^2 = **1/4**, or 1:4. I hope that helped!

Ziggy Nov 24, 2020

#2

#3**+2 **

Best Answer

Sure, I can try! First, we can call the side length of the square "x". The area of this orginal square would be x^2. Next, if the length of the side of the square was doubled, then one side would have a length of 2*x = 2x. The area of this new sqaure would be (2x)^2 = 4x^2. Therefore, the ratio of the areas of the original sqaure and the area of the new sqaure is x^2 / 4x^2 = **1/4**, or 1:4. I hope that helped!

Ziggy
Nov 24, 2020