If $x$ and $y$ are numbers such that $9^x-4^y=10$ and $3^x-2^y=2$, compute $3^x+2^y$.
(3x - 2y)(3x + 2y) = 9x - 4y
We know 3x - 2y = 2 and 9x - 4y = 10
( 2 )( 3x + 2y ) = 10
Divide both sides of the equation by 2
3x + 2y = 5
