AB and AC are equal legs in triangle ABC. Point D lies on AB such that CD = CB. If angle ADC = 114 degrees, what is angle ACD in degrees?
$\angle ACD = 22^\circ$.
Angle ACD = 18 degrees
ADC =114 so we know BDC is then equal to 66 (180-114)
DBC is also equal to BDC because its an isosceles traingle, DBC and BDC = 66
180-(66+66)=48
because AB and AC are equal sides, ABC and ACB are both equal to 66
66-48=12 :)
