Let f(x)=sin^-1x . Then the domain of f(x) is [-1,1] and the range is all real numbers.
True or False?
+499 True, as the inverse sine allows any x value between -1 and 1(that's the max and minimum of sine). The range is also all real numbers, as sine can go negative or positive.
+2094 I agree! This is true. The inverse sin allows the max and minimum x value between the domain.
We know from f(x)=sin^-x that the range is all real numbers since x can be any real number.
Hope this helped!
