Let f(x)=sin^-1x . Then the domain of f(x) is [-1,1] and the range is all real numbers.

True or False?

Guest Mar 21, 2020

#1**+1 **

True, as the inverse sine allows any x value between -1 and 1(that's the max and minimum of sine). The range is also all real numbers, as sine can go negative or positive.

jfan17 Mar 21, 2020

#2**+1 **

I agree! This is true. The inverse sin allows the max and minimum x value between the domain.

We know from f(x)=sin^-x that the range is all real numbers since x can be any real number.

Hope this helped!

CalTheGreat Mar 21, 2020