Three runners Adam, Ben, and Charles all start at the same time for a 24 km race, and each of them runs at a constant speed. When Adam finishes the race, Ben is 8 km behind, and Charles is 12 km behind. When Ben finishes the race, how far behind is Charles, in km?
Three runners Adam, Ben, and Charles all start
at the same time for a 24 km race,
and each of them runs at a constant speed.
When Adam finishes the race, Ben is 8 km behind, and Charles is 12 km behind.
When Ben finishes the race, how far behind is Charles, in km?
Formula \(s=v*t\)
\(\begin{array}{|lrcll|} \hline (1) & 24~\text{km} &=& v_{Adam}*t_{Adam} \\ (2) & 24~\text{km}-8~\text{km} &=& v_{Ben}*t_{Adam} \\ &\mathbf{ v_{Ben}} &=& \mathbf{\dfrac{16}{t_{Adam}} } \\\\ (3) & 24~\text{km}-12~\text{km} &=& v_{Charles}*t_{Adam} \\ & \mathbf{v_{Charles}} &=& \mathbf{ \dfrac{12}{t_{Adam}} } \\ \hline \end{array}\)
\(\begin{array}{|rcll|} \hline s_{Ben}=24~\text{km} &=& v_{Ben}*t_{Ben} \quad |\quad \mathbf{ v_{Ben}=\dfrac{16}{t_{Adam}} } \\ \\ 24 &=& \dfrac{16}{t_{Adam}}*t_{Ben} \\\\ \dfrac{t_{Ben}}{t_{Adam}} &=& \dfrac{24}{16} \\ \\ \mathbf{ \dfrac{t_{Ben}}{t_{Adam}} } &=& \mathbf{1.5 } \\\\ \hline s_{Charles} &=& v_{Charles}*t_{Ben} \quad |\quad \mathbf{v_{Charles}=\dfrac{12}{t_{Adam}} } \\ \\ s_{Charles} &=& \dfrac{12}{t_{Adam}}*t_{Ben} \\ \\ s_{Charles} &=& 12*\dfrac{t_{Ben} }{t_{Adam}} \quad | \quad \mathbf{ \dfrac{t_{Ben}}{t_{Adam}} = 1.5 } \\\\ s_{Charles} &=& 12* 1.5 \\\\ s_{Charles} &=& 18~\text{km} \\ \hline s_{Ben}-s_{Charles} &=& 24~\text{km}-18~\text{km}\\ \mathbf{s_{Ben}-s_{Charles}} &=& \mathbf{6~\text{km}} \\ \hline \end{array}\)
Charles is \(\mathbf{6~\text{km}}\) behind
OK... lets say adam runs at 24 km /hr finishes in 1 hour
charles is 12 km behind .....he is only 1/2 way through....must be running at 12 km/hr he will finish in 2 hours
ben is 8km behind he has run 16 km in one hour 16 km/hr he will finish in 1 1/2 hour
Charles done in 2 hours
whne Ben finishes Charles is still 30 minutes behind x 12/km/hr = 6 km
Three runners Adam, Ben, and Charles all start at the same time for a 24 km race, and each of them runs at a constant speed. When Adam finishes the race, Ben is 8 km behind, and Charles is 12 km behind. When Ben finishes the race, how far behind is Charles, in km?
Drei Läufer, Adam, Ben und Charles, starten alle gleichzeitig für ein 24-km-Rennen, und jeder von ihnen läuft mit einer konstanten Geschwindigkeit. Als Adam das Rennen beendet hat, liegt Ben 8 km und Charles 12 km zurück. Wenn Ben das Rennen beendet, wie weit ist Charles zurück.
Hello Guest!
\(v=\frac{s}{t}\\ t=\frac{s}{v}\\ s=vt\)
\(\frac{24}{v_a}=\frac{16}{v_b}=\frac{12}{v_c}\)
\(\frac{v_b}{16}=\frac{v_c}{12}\\ v_c=\frac{3}{4}v_b\)
\(\frac{24km}{v_b}=\frac{24km-x}{v_c}\\ \frac{24km}{v_b}=\frac{24km-x}{\frac{3}{4}v_b}\\ 3\cdot 24km=4(24km-x)\\ 72km=96km-4x\\ 4x=(96-72)km\)
\(x=6km\)
Charles is 6km behind.
!