Two circles with radius 1 are externally tangent at B, and have line AB and line BC as diameters. A tangent to the circle with diameter BC passes through A, and a tangent to the circle with diameter AB passes through C, so that the tangent lines are parallel. Find the distance between the two tangent lines.
Let the center of circle with diameter AB be O. Let the circle with diameter BC have center Q.
Let the tangent to circle O be M. Let the tangent to circle Q be N.
Then $\triangle QNA$ is right. The length QA is 3, and it is the hypotenuse, and QN is a radius, so it equals 1.
If we extend QN downward until it intersects MC at point X, we have that our desired distance is XN.
By AA similarity, $\triangle ANQ \sim CXQ,$ so $\frac{NQ}{AQ} = \frac{QX}{QC} \Longrightarrow \frac{1}{3} = QX \Longrightarrow QX + DQ = \frac{4}{3} !!!!$