Sam and Janet each have a whole number of dollars, and 1/3 of Sam's money equals of 1/2 Janet's money. Together, they have more than $10. What is the least number of dollars they could have combined?
+115 Lowest possible solution is 3,2
If we just multiply the numbers by the same factor which would be large enough that the sum of both integers is more than 10,
3,2 x 4
we get 12,8
+36916 Sam = s Jane = j
1/3 s = 1/2 j
s = 3/2 j
s+j = 10 (more than 10 actually)
3/2j + j = 10
5/2j =10
j = 4 so s = 3/2j = 6 if it EQUALS 10....we want the next whole numbers that are greater than 10
j=6 and s = 9 would be the next whole number amounts that would work total $ 15
