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Solve the equation on the interval [0,2π) .

−8cosx=3

 Apr 8, 2020
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Solve the equation on the interval [0,2π) .
−8cosx=3

 

Hello Guest!

 

  8cos(x)=3                                 | :(8)       

       cos(x)=38                            

                x=arccos(0.375)

                x1=1.955x2=4.328

  laugh  !

 Apr 8, 2020
edited by asinus  Apr 8, 2020

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