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Solve the equation on the interval [0,2π) .

−8cosx=3

 Apr 8, 2020
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Solve the equation on the interval [0,2π) .
−8cosx=3

 

Hello Guest!

 

  \(−8cos(x)=3 \)                                 | \(:(-8)\)       

       \(cos(x)=-\frac{3}{8}\)                            

                \(x=arccos(-0.375)\)

                \(x_1 = 1.955\\ x_2=4.328\)

  laugh  !

 Apr 8, 2020
edited by asinus  Apr 8, 2020

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