Find \(1_6 + 2_6 + 3_6 + \cdots + 45_6\). Express your answer in base 6.
456 = 4(6) + 5 = 2910
So... the sum of the first 29 integers in base 10 = (29)(30)/ 2 = 435
Converting this to base 6, we have
435 / 8 = 72 R 3
72 / 6 = 12 R 0
12 / 6 = 2 R 0
2 / 6 = 0 R 2 =
20036
