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# Help

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Let e(x) be an even function, and let o(x) be an odd function, such that

$$e(x) + o(x) = \frac{6}{x + 2} + x^2 + 2^x$$

for all real numbers x. Find o(1).

Jul 27, 2019

#1
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Let e(x) be an even function, and let o(x) be an odd function, such that

$$e(x) + o(x) = \frac{6}{x + 2} + x^2 + 2^x$$

for all real numbers x. Find o(1).

$$e(x)=x^2+2^x\ \{even\ function \}\\ o(x)=\frac{6}{x+2}\ \{odd\ function\}\\ \color{blue} o(1)=\frac{6}{1+2}=2$$

$$e(x) + o(x) =(x^2+2^x)+( \frac{6}{x + 2} )$$

!

Jul 27, 2019
edited by asinus  Jul 27, 2019
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Um I am sorry but this answer is incorrect

Jul 28, 2019