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Find \( \csc\theta\) if tan \(\theta\) = 5/12 and \(\theta\) is in Quadrant III.

 Oct 15, 2019
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tan A  =  y / x  = -5/-12  =  5/12

 

csc A =   r / y

 

r =  sqrt (5^2 + 12^2)  =  sqrt (25 + 144)  = sqrt (169)  = 13

 

Since  y is negative in Q3....then csc A =   13/-5  =  -13/5

 

 

cool cool cool

 Oct 15, 2019

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