Find \( \csc\theta\) if tan \(\theta\) = 5/12 and \(\theta\) is in Quadrant III.
tan A = y / x = -5/-12 = 5/12
csc A = r / y
r = sqrt (5^2 + 12^2) = sqrt (25 + 144) = sqrt (169) = 13
Since y is negative in Q3....then csc A = 13/-5 = -13/5
+220 
