+0  
 
0
170
4
avatar+2509 

Help.

NotSoSmart  Feb 1, 2018
 #1
avatar
+1

2)

Solve for x:

4(3 - x)^4/3 - 5 = 59       add 5 to both sides

4(3 - x)^4/3 = 64            divide both sides by 4

(3 - x)^4/3 = 16              raise both sides to 3rd power

(x - 3)^4 = 4096

 

Taking 4^th roots gives 8 times the 4^th roots of unity:

x - 3 = -8 or x - 3 = -8 i or x - 3 = 8 i or x - 3 = 8

 

Add 3 to both sides:

x = -5 or x - 3 = -8 i or x - 3 = 8 i or x - 3 = 8

 

Add 3 to both sides:

x = -5 or x = 3 - 8 i or x - 3 = 8 i or x - 3 = 8

 

Add 3 to both sides:

x = -5 or x = 3 - 8 i or x = 3 + 8 i or x - 3 = 8

 

Add 3 to both sides:

x = -5 or x = 3 - 8 i or x = 3 + 8 i or x = 11 - Discard the imaginary solutions:

x = -5       and          x = 11

Guest Feb 1, 2018
 #2
avatar+87639 
+1

1.   Not too bad,  NSS

 

√[ x + 10 ] - 9  = 7   add  9 to both sides

 

√ [ x + 10 ]   =  2        square both sides

 

x + 10  =  4       subtract 10 from both sides

 

x  = -6

 

 

cool cool cool

CPhill  Feb 1, 2018
edited by CPhill  Feb 1, 2018
edited by CPhill  Feb 1, 2018
 #3
avatar+2509 
+1

would 2 be A??

NotSoSmart  Feb 1, 2018
 #4
avatar
+1

Yes, the 1st one: -5, 11

Guest Feb 1, 2018

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