Find the value of a
\(\begin{align*} y &= 11x+14 \\ 2y-4 &= ax \end{align*}\) so that the system has no solutions.
+36916 Multiply first equation by - 2
-2y = -22x - 28 add second equation
2y-4=ax
-4 = -22x + ax - 28
24 = -22x + ax
24 = x(a-22)
24/(a-22) = x as you can see, when the denominator = 0 this is invalid....this occurs when a = 22
