+60 find the standard equation of the circle of radius 2 that are tangent to both the line x=1 and y=3 .
The radius is 2 so we know the center will be 2 from x = 1 h = 3
and the center will be 2 away frm y = 3 k=1
h,k = 3,1 r^2 = 4
(x-3)^2 + (y-1)^2 = 4
+128475 Actually....we have four possibilities......
The center of the first circle is (3, 1)
Its equation is (x - 3)^2 + (y - 1)^2 =4
Another possibility is a circle with a center of ( 3, 5)
Its equation is ( x - 3)^2 + ( y - 5)^2 = 4
Two other possibilites
A circle with a center of (-1, 1)
Equation is ( x + 1)^2 + ( y - 1)^2 = 4
A circle with a center (-1,5)
Equation is ( x + 1)^2 + ( y - 5)^2 = 4
See the graph here : https://www.desmos.com/calculator/lgpofoe62f
