Given that A and B are acute angles such that cos(A-B) = 3/4 and sinAsinB = 5/8. Without using a calculator, find the value of cotA/tanB.
+130536 Given that A and B are acute angles such that cos(A-B) = 3/4 and sinAsinB = 5/8. Without using a calculator, find the value of cotA/tanB.
cos(A - B) = cosAcosB + sinAsinB ...so....
3/4 = cosAcosB + 5/8
1/8 = cosAcosB
cotA/tanB = cotAcotB = cosAcosB / [ sinAsinB ] = [1/8] / [5/8] = [1/8] * [ 8/5] = 1/5
