+0  
 
0
86
1
avatar+235 

Given that 2^x=7, find the value of 4^(x-1).

 Aug 15, 2020
 #1
avatar+1039 
+4

We can rewrite 4^(x-1) as 4^x/4. 4^x can be rewritten as (2^x)^2, which is 7^2, which is 49. So, the answer is 49/4, which is 12.25 in decimal form.

 

:)

 Aug 15, 2020

12 Online Users