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In trapezoid $PQRS,$ $\overline{PQ} \parallel \overline{RS}$.  Let $X$ be the intersection of diagonals $\overline{PR}$ and $\overline{QS}$.  The area of triangle $PQX$ is $2,$ and the area of triangle $RSX$ is $2.$  Find the area of trapezoid $PQRS$.

 Jul 31, 2025
 #1
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The area of trapezoid PQRS is 8 + 10*sqrt(5).  I hope this helps!

 Jul 31, 2025

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