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A ship leaves a port and travels along a bearing of 165 degrees for 270km. To avoid an incoming storm, it then changes course to a bearing of 203 degrees for another 130km and anchors. Find its bearing and distance from port

 Jul 21, 2019
 #1
avatar+19325 
+2

165 degrees   magnitude   270    firnd the x and y components

x = 270 cos 165 =  - 260.8

y = 270 sin 165 = 69.9  

 

203 degrees magnitude 130   find the x and y components

x = 130 cos 203  =  -119.7    (edited)

y=  130 sin 203 =  -50.8        (edited)

 

Add the x components and the y components

x =- 260.8+-119.7 = -380.5

y = 69.9 - 50.8 = 19.1

 

d = sqrt (x^2 + y^2) = 381 km  from origin   bearing = arctan (y/x) = 177.1 degrees

 Jul 21, 2019
edited by Guest  Jul 21, 2019
edited by Guest  Jul 21, 2019
 #2
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+1

Thank you very much!!!   smiley

Guest Jul 21, 2019
 #3
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How are you able to find the bearing?

Guest Jul 22, 2019
 #4
avatar+19325 
+2

  bearing = arctan (y/x) = 177.1 degrees

ElectricPavlov  Jul 22, 2019

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