+22 3(7y-6)^2 - 166 = 26 how do i solve this? the answer is y = 2 or -2/7
3(7y - 6)^2 - 166 = 26
1. Collect all the variables and constants onto one side
3(7y - 6)^2 - 192 = 0
2. Expand the brackets
3(7y - 6)(7y - 6) - 192 = 0
3(49y^2 - 84y + 36) - 192 = 0
147y^2 - 252y + 108 - 192 = 0
147y^2 - 252y - 84 = 0
3. Solve for x by either factorising, completing the square, or using the quadratic formula
Factors: 21(y - 2)(7y + 2)
Solutions: y = 2, y = -2/7
3(7y - 6)^2 - 166 = 26
1. Collect all the variables and constants onto one side
3(7y - 6)^2 - 192 = 0
2. Expand the brackets
3(7y - 6)(7y - 6) - 192 = 0
3(49y^2 - 84y + 36) - 192 = 0
147y^2 - 252y + 108 - 192 = 0
147y^2 - 252y - 84 = 0
3. Solve for x by either factorising, completing the square, or using the quadratic formula
Factors: 21(y - 2)(7y + 2)
Solutions: y = 2, y = -2/7
