In right triangle ABC, we have AB = 10, BC = 24, and angle ABC = 90. If M is on AC such that BM is an angle Bisector if triangle ABC, what is cos ABM?
A
10 M cos ABM
B 24 C
Since BM is an angle bisector of right angle ABC....then angle ABM = (1/2)(90°) = 45°
So....the cos ABM = cos (45°) = 1 / √2
+188 
