Help. ​

(3x+2)(3x-2)

This problem is what is known as a difference of perfect squares.

The standard form of this is $(ax^2-b^2)=(\sqrt{a}x+\sqrt{b})(\sqrt{a}x-\sqrt{b})$.

In this the a=9 and the b=4.

So $(9x^2-4)=(3x-2)(3x+2)$.