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# Help. ​

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Help.

Nov 1, 2017

#1
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(3x+2)(3x-2)

Nov 1, 2017
#2
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This problem is what is known as a difference of perfect squares.

The standard form of this is $$(ax^2-b^2)=(\sqrt{a}x+\sqrt{b})(\sqrt{a}x-\sqrt{b})$$.

In this the a=9 and the b=4.

So $$(9x^2-4)=(3x-2)(3x+2)$$.

Nov 2, 2017