Find the smallest value of x such that \(x^2 + 10x + 25 = 8\)
By the quadratic forrmula, the smallest root is x = -5 - 4*sqrt(3).
x2 +10x + 25 = 8
x2 +10x +17 = 0
x = -5 +2√2 or x = -5 -2√2