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What is the range of the function f(x)=3x^2+6x-8

 Apr 10, 2020
 #1
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f(x)  =  3x^2  + 6x  - 8

 

The  x coordinate  of the vertex =  -6 / [ 2 * 3]  =  -6/6  =  -1

 

This is a parabola  that turns upward......the vertex  is the minimum point

 

The  y coordinate  of the vertex =  3(-1)^2  + 6(-1) - 8  =  3 - 6 - 8  =  -11

 

So.....the range  is     [ -11, infinity )

 

 

cool cool cool

 Apr 10, 2020

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