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In triangle XYZ, XZ=7, YZ=7, and XY=6. What is the area of the triangle in simplified radical form?

 Apr 7, 2020
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Let  XY  be  the  base  and  XZ  and YZ  be  the sides

 

Using  the Pythagorean Theorem we  can find the height  as

 

√[ YZ^2- (XY/2)^2 ] =  √ [ 7^2  - (3)^2 ]  =  √[49 - 9] = √40  =  2√10

 

So...the area   =  (1/2)(XY) (height)  = (1/2)(6) (2√10)  =  3  (2√10)  =   6√10  [units^2]

 

 

cool cool cool

 Apr 7, 2020

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