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Find the minimum value of \(2x^2+2xy+y^2+2x-3y+8\) for real numbers x and y.

 Jul 8, 2020
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Use the formula x=−b/2a to find the maximum and minimum.

(0,y^2−3y+8). Hope this helps, whymenotsmart^m^

 Jul 8, 2020

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