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One man is three times as old as another. Fifteen years ago the first was six times as old as the second. Find their ages now.

 Apr 25, 2020
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Now   x = 3y

 

15 years ago    (x-15) = 6(y-15)     or   x -15 = 6y-90      or x = 6y-75     Put this in for 'x' in the first equation

6y-75 = 3y

3y = 75

y = 25 y/o

 

x = 75 y/o

 Apr 25, 2020

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