One man is three times as old as another. Fifteen years ago the first was six times as old as the second. Find their ages now.
Now x = 3y
15 years ago (x-15) = 6(y-15) or x -15 = 6y-90 or x = 6y-75 Put this in for 'x' in the first equation
6y-75 = 3y
3y = 75
y = 25 y/o
x = 75 y/o