The equation of the circle that passes through (-1,6) and which has a center at (2,3) can be written as x^2 + y^2 + Ax + By + C = 0. Find A * B * C.
The equation of the circle is x^2 + y^2 - 7x + 3y + 10 = 0, so A*B*C = (-7)(3)(10) = -210.
You can work out the radius first.
then use the equation of a circle centre (h,k) formula (you can google it if you do not know it)
Sub in the values of h, k, and r to get the formula for the circle.
Rearrange to find AB and C
Ask questions if you want but show evidence that you have done something for yourself first.
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