Determine the remainder when x3 + 3x2 – x – 2 is divided by (x + 3)(x+ 5)
Suggestion: multiply out the divisor: (x + 3)(x + 5) = x2 + 8x + 15
Then use long-division to divide x3 + 3x2 - x - 2 by x2 + 8x + 15
[Your remainder will have both an x-term and a constant in it.]
Here's an alternative approach that doesn't require long division: