Find the x-intercept of the line 3x-5y=7.
\(\begin{array}{|rcll|} \hline 3x-5y &=& 7 \quad | \quad x\text{-intercept}~(y=0) \\\\ 3x-5*0 &=& 7 \\ 3x &=& 7 \\ \mathbf{x} &=& \mathbf{\dfrac{7}{3}} \qquad (x=2.\bar{3}) \\ \hline \end{array} \)
\((2.\bar{3},~0)\)
